Verified answer

The new area of the square is [tex]36cm^{2}[/tex]

GIven:

Are of the square is [tex]16cm[/tex].

To Find:

Area of the square if its length is increased by [tex]2cm[/tex].

Solution:

Let the initial length of the side be [tex]a[/tex]

So, are will be [tex]a^{2}[/tex]

And

[tex]a^{2} =16\\a=4[/tex]

Now the length is increased by [tex]2cm[/tex].

So,

The new length is [tex]4+2=6cm[/tex]

Now the new area will be

[tex]=6^{2}\\ =36cm^{2}[/tex]

Hence, The new area of the square is [tex]36cm^{2}[/tex].

Given:

the area of a square is 16 cm2

Formula Used:

area of a square = a2; where a = side of square

Calculation:

F1 Ravi.S 09-11-20 Savita D2

⇒ GF2 = DG2 + DF2

⇒ GF2 = 22 + 22

⇒ GF = 2√2 cm

similarly, FE = EH = GH = 2√2 cm, so, EFGH is also a square

⇒ area of square EFGH = (2√2)2 = 8 cm2

∴ required area = 8 cm2