Answer:
Q1 a part :-->
[tex]3x + 2x + x = 180(in \: a \: triangle \: the \: sum \: f \: all \: sides \: is \: 180) \\ 5x + x = 180\\ x + x = \frac{180}{5 } \\ x + x = 36 \\ 2x = 36 \\ x = \frac{36}{2} \\ x = 18[/tex]
Step-by-step explanation:
[tex](1) \: (a)\: x + 2x + 3x = 180 \\ x = \frac{180}{6} = 30 \\ \\ (b) \: 45 + 65 = x \\ x = 110 \\ \\ \\ (2) \: le t \: te \: angles \: be \: 2x \: \: 3x \: \: 5x \\ 2x + 3x + 5x = 180 \\ x = \frac{180}{10} = 18 \\ \\ angles \: are \: \: 2\times18 = 36 \\ 3 \times 18 = 54 \\ 5 \times 18 = 90 \: \\ \\ \\ (3) \: p = 30 + q \\ r = 90 \\ \\ = > p + q + r = 180 \\ = > 30 + q + q + 90 = 180 \\ = > q = \frac{180 - 120}{2} = 30 \\ \\ p = 30 + 30 = 60 \\ q = 30 \\ r = 30 \\ \\ \\ (4) \\ (a) \: 70 + x = 100 \\ x = 100 - 70 = 30 \: \: \: \: \: \: \\ by \: the \: triangle \\ \: \: \: \: \: \: \: \: \: \: \: \: property \\ \\ (b) \: 45 + 30 = x \\ x = 75[/tex]
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Answer:
Q1 a part :-->
[tex]3x + 2x + x = 180(in \: a \: triangle \: the \: sum \: f \: all \: sides \: is \: 180) \\ 5x + x = 180\\ x + x = \frac{180}{5 } \\ x + x = 36 \\ 2x = 36 \\ x = \frac{36}{2} \\ x = 18[/tex]
Verified answer
Step-by-step explanation:
[tex](1) \: (a)\: x + 2x + 3x = 180 \\ x = \frac{180}{6} = 30 \\ \\ (b) \: 45 + 65 = x \\ x = 110 \\ \\ \\ (2) \: le t \: te \: angles \: be \: 2x \: \: 3x \: \: 5x \\ 2x + 3x + 5x = 180 \\ x = \frac{180}{10} = 18 \\ \\ angles \: are \: \: 2\times18 = 36 \\ 3 \times 18 = 54 \\ 5 \times 18 = 90 \: \\ \\ \\ (3) \: p = 30 + q \\ r = 90 \\ \\ = > p + q + r = 180 \\ = > 30 + q + q + 90 = 180 \\ = > q = \frac{180 - 120}{2} = 30 \\ \\ p = 30 + 30 = 60 \\ q = 30 \\ r = 30 \\ \\ \\ (4) \\ (a) \: 70 + x = 100 \\ x = 100 - 70 = 30 \: \: \: \: \: \: \\ by \: the \: triangle \\ \: \: \: \: \: \: \: \: \: \: \: \: property \\ \\ (b) \: 45 + 30 = x \\ x = 75[/tex]