Answer with solution wrong answer and no solution report
The distance x from the point of departure at time t is defined by the equation x=-16t^2+5000t+5000, what is the initial velocity?
The distance x from the point of departure at time t is defined by the equation x=-16t^2+5000t+5000, what is the initial velocity?
Answers & Comments
Verified answer
Answer:
I'll try
Substitute
a.)
s=120(1)-16(1)²
s=120-16(1)
s=120-16
s=114
b.)
s=120(2)-16(2)²
s=240-16(4)
s=240-64
s=176
c.)
s=120(3)-16(3)²
s=360-16(9)
s=360-144
s=216
Step-by-step explanation: