Step-by-step explanation:
[tex]we \: are \: given \: the \: equation \\ \\ 6 \sqrt{3} {x}^{2} - 47x + 5 \sqrt{3} \\ 6 \sqrt{3} {x}^{2} - 45x - 2x + 5 \sqrt{3} \\ 3 \sqrt{3} x(2x - 5 \sqrt{3} ) - 1(2x - 5 \sqrt{3} ) \\ (3 \sqrt{3}x - 1)(2x - 5 \sqrt{3} ) \\ \\ hence \: factorised \\ \\ or \: if \: you \: want \: the \: roots \: of \: equation \: then \\ (3 \sqrt{3}x - 1)(2x - 5 \sqrt{3}) = 0 \\ \\ case1 \: \: \: \: \: \: \: \: \: \: case2 \\ 3 \sqrt{3} x - 1 = 0 \: \: \: \: \: \: \: \: \: \: 2x - 5 \sqrt{3} = 0 \\ 3 \sqrt{3} x = 1 \: \: \: \: \: \: \: \: \: \: 2x = 5 \sqrt{3} \\ x = \frac{1}{3 \sqrt{3} } \: \: \: \: \: \: \: \: \: \: \: \: x = \frac{5 \sqrt{3} }{2} \\ \\ hence \: x = \frac{1}{3 \sqrt{3} } \: and \: \frac{5 \sqrt{3} }{2} \\ hope \: it \: helps \\ take \: care[/tex]
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Step-by-step explanation:
[tex]we \: are \: given \: the \: equation \\ \\ 6 \sqrt{3} {x}^{2} - 47x + 5 \sqrt{3} \\ 6 \sqrt{3} {x}^{2} - 45x - 2x + 5 \sqrt{3} \\ 3 \sqrt{3} x(2x - 5 \sqrt{3} ) - 1(2x - 5 \sqrt{3} ) \\ (3 \sqrt{3}x - 1)(2x - 5 \sqrt{3} ) \\ \\ hence \: factorised \\ \\ or \: if \: you \: want \: the \: roots \: of \: equation \: then \\ (3 \sqrt{3}x - 1)(2x - 5 \sqrt{3}) = 0 \\ \\ case1 \: \: \: \: \: \: \: \: \: \: case2 \\ 3 \sqrt{3} x - 1 = 0 \: \: \: \: \: \: \: \: \: \: 2x - 5 \sqrt{3} = 0 \\ 3 \sqrt{3} x = 1 \: \: \: \: \: \: \: \: \: \: 2x = 5 \sqrt{3} \\ x = \frac{1}{3 \sqrt{3} } \: \: \: \: \: \: \: \: \: \: \: \: x = \frac{5 \sqrt{3} }{2} \\ \\ hence \: x = \frac{1}{3 \sqrt{3} } \: and \: \frac{5 \sqrt{3} }{2} \\ hope \: it \: helps \\ take \: care[/tex]