trigonometry;
we have to prove :
LHS
we know that
then ,
[ use( a+b) ( a-b) = a^2 - b^2]
=
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step by step explanation:
trigonometry;
we have to prove :
LHS
we know that
then ,
LHS
[ use( a+b) ( a-b) = a^2 - b^2]
I hope it helps you
ANSWER:-
➣
• To Prove :
SOLUTION:-
• LHS
=![\frac{1 + ( \sec( \alpha ) - \tan( \alpha ) ) }{1 + ( \sec( \alpha ) + \tan( \alpha ) ) } \frac{1 + ( \sec( \alpha ) - \tan( \alpha ) ) }{1 + ( \sec( \alpha ) + \tan( \alpha ) ) }](https://tex.z-dn.net/?f=%5Cfrac%7B1%20%2B%20%28%20%5Csec%28%20%5Calpha%20%29%20-%20%5Ctan%28%20%5Calpha%20%29%20%29%20%7D%7B1%20%2B%20%28%20%5Csec%28%20%5Calpha%20%29%20%2B%20%5Ctan%28%20%5Calpha%20%29%20%29%20%7D)
As we know:-
Therefore ,
LHS
We know:-
• RHS:-
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L.H.S = R.H.S
Hence Proved ✅