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[tex] \large\underline{\mathbb{ANSWER}:} [/tex]
[tex] \qquad\Large\rm 1) \ \ m\angle X = 38 \degree [/tex]
[tex] \qquad\Large\rm 2) \ \ m\overset{\frown}{CH}= 22\degree [/tex]
[tex] \qquad\Large\rm 3) \: \: m\overset{\frown}{CH}= 90\degree [/tex]
[tex] \qquad\Large\rm 4) \:\: m\angle X = 45 \degree [/tex]
[tex] \qquad\Large\rm 5) \: \: m\overset{\frown}{LP} = 150 \degree [/tex]
[tex] \large\underline{\mathbb{SOLUTION}:} [/tex]
#1: The measure of the angle formed at the exterior of a circle is one half the positive difference of its intercepted arcs.
[tex] \therefore [/tex] Angle X is 38 degrees.
[tex]••• \: ••• \: •••\: •••\:•••\:•••\:•••\:•••\:•••\:•••\:•••\:•••\:•••[/tex]
#2: The measure of the angle formed at the exterior of a circle is one half the positive difference of its intercepted arcs.
[tex] \therefore [/tex] Arc CH is 22 degrees.
#3: The measure of the angle formed at the exterior of a circle is one half the positive difference of its intercepted arcs.
[tex] \therefore [/tex] Arc CH is 90 degrees.
#4: The measure of the angle formed at the exterior of a circle is one half the positive difference of its intercepted arcs.
[tex] \therefore [/tex] Angle X Is 45 degrees.
#5: The measure of the angle formed at the exterior of a circle is one half the positive difference of its intercepted arcs.
[tex] \therefore [/tex] Arc LP is 150 degrees.
I HOPE THIS HELPS :)
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[tex]••••••••••••••••••••••••••••••••••••••••••••••••••[/tex]
[tex] \large\underline{\mathbb{ANSWER}:} [/tex]
[tex] \qquad\Large\rm 1) \ \ m\angle X = 38 \degree [/tex]
[tex] \qquad\Large\rm 2) \ \ m\overset{\frown}{CH}= 22\degree [/tex]
[tex] \qquad\Large\rm 3) \: \: m\overset{\frown}{CH}= 90\degree [/tex]
[tex] \qquad\Large\rm 4) \:\: m\angle X = 45 \degree [/tex]
[tex] \qquad\Large\rm 5) \: \: m\overset{\frown}{LP} = 150 \degree [/tex]
[tex]••••••••••••••••••••••••••••••••••••••••••••••••••[/tex]
[tex] \large\underline{\mathbb{SOLUTION}:} [/tex]
#1: The measure of the angle formed at the exterior of a circle is one half the positive difference of its intercepted arcs.
[tex] \therefore [/tex] Angle X is 38 degrees.
[tex]••• \: ••• \: •••\: •••\:•••\:•••\:•••\:•••\:•••\:•••\:•••\:•••\:•••[/tex]
#2: The measure of the angle formed at the exterior of a circle is one half the positive difference of its intercepted arcs.
[tex] \therefore [/tex] Arc CH is 22 degrees.
[tex]••• \: ••• \: •••\: •••\:•••\:•••\:•••\:•••\:•••\:•••\:•••\:•••\:•••[/tex]
#3: The measure of the angle formed at the exterior of a circle is one half the positive difference of its intercepted arcs.
[tex] \therefore [/tex] Arc CH is 90 degrees.
[tex]••• \: ••• \: •••\: •••\:•••\:•••\:•••\:•••\:•••\:•••\:•••\:•••\:•••[/tex]
#4: The measure of the angle formed at the exterior of a circle is one half the positive difference of its intercepted arcs.
[tex] \therefore [/tex] Angle X Is 45 degrees.
[tex]••• \: ••• \: •••\: •••\:•••\:•••\:•••\:•••\:•••\:•••\:•••\:•••\:•••[/tex]
#5: The measure of the angle formed at the exterior of a circle is one half the positive difference of its intercepted arcs.
[tex] \therefore [/tex] Arc LP is 150 degrees.
[tex]••••••••••••••••••••••••••••••••••••••••••••••••••[/tex]
I HOPE THIS HELPS :)