2. To find the square of (5x - 5) using the generic method, we would multiply (5x - 5) by (5x - 5) to get (5x - 5)(5x - 5) = 25x^2 - 50x + 25x - 25 = 25x^2 - 25.
3. To find the product of ( (-4)² + 1) and (5^2-2) using the generic method, we would first evaluate the expressions in the parentheses to get (16 + 1) and (25 - 2), respectively. Then we would multiply these numbers together to get (17)(23) = 391.
4. To find the product of (8z - 5) and (8z + 5) using the generic method, we would multiply these binomials together using the distributive property to get (8z - 5)(8z + 5) = 64z^2 - 40z + 40z - 25 = 64z^2 - 25.
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Answer:
2. To find the square of (5x - 5) using the generic method, we would multiply (5x - 5) by (5x - 5) to get (5x - 5)(5x - 5) = 25x^2 - 50x + 25x - 25 = 25x^2 - 25.
3. To find the product of ( (-4)² + 1) and (5^2-2) using the generic method, we would first evaluate the expressions in the parentheses to get (16 + 1) and (25 - 2), respectively. Then we would multiply these numbers together to get (17)(23) = 391.
4. To find the product of (8z - 5) and (8z + 5) using the generic method, we would multiply these binomials together using the distributive property to get (8z - 5)(8z + 5) = 64z^2 - 40z + 40z - 25 = 64z^2 - 25.