Step-by-step explanation:
[tex]to \: find : value \: of \: f(2) \\ \\ given \: that : \\ f( \frac{x + 1}{x + 2} ) = \frac{x {}^{2} - 1 }{x {}^{2} + 2 } \\ \\ for \: \: f(2) \: \\ we \: must \: take \: \: \frac{x + 1}{x + 2} = 2 \\ \\ x + 1 = 2x + 4 \\ \\ x = - 3[/tex]
[tex]so \: now \\ f(2) = \frac{x {}^{2} - 1 }{x {}^{2} + 2 } \\ \\ = \frac{( - 3) {}^{2} - 1 }{( - 3) {}^{2} + 2 } \\ \\ = \frac{9 - 1}{9 + 2} \\ \\ f(2)= \frac{8}{11} [/tex]
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Step-by-step explanation:
[tex]to \: find : value \: of \: f(2) \\ \\ given \: that : \\ f( \frac{x + 1}{x + 2} ) = \frac{x {}^{2} - 1 }{x {}^{2} + 2 } \\ \\ for \: \: f(2) \: \\ we \: must \: take \: \: \frac{x + 1}{x + 2} = 2 \\ \\ x + 1 = 2x + 4 \\ \\ x = - 3[/tex]
[tex]so \: now \\ f(2) = \frac{x {}^{2} - 1 }{x {}^{2} + 2 } \\ \\ = \frac{( - 3) {}^{2} - 1 }{( - 3) {}^{2} + 2 } \\ \\ = \frac{9 - 1}{9 + 2} \\ \\ f(2)= \frac{8}{11} [/tex]