Answer:
Given in △ ABC, ∠B=90°.
This given A+C=180°−90°=90°
Now,
sinA.cosC+cosA.sinC
=sin(A+C)
Given in △ ABC, ∠B=90°
sin(A+C)
sin(90°)
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Answer:
Given in △ ABC, ∠B=90°.
This given A+C=180°−90°=90°
Now,
sinA.cosC+cosA.sinC
=sin(A+C)
Given in △ ABC, ∠B=90°
This given A+C=180°−90°=90°
sinA.cosC+cosA.sinC
sin(A+C)
sin(90°)