The force would accelerate the 400kg mass by 3m/s² .
Given that ,a force (F) accelerates a body of mass 600kg by 2m/s².
So, firstly let's calculate the force (F) by Newton's 2nd law of motion :-
F = ma
Where :-
• F is the force.
• m is mass of the body.
• a is the acceleration.
Substituting values, we get :-
⇒ F = 600(2)
⇒ F = 1200 N
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Now, in the 2nd case we have :-
• m' = 400 kg
• F = 1200 N
• a' = ?
Again substituting values in the 2nd equation of motion, we get :-
⇒ F = m'a'
⇒ a' = F/m'
⇒ a' = 1200/400
⇒ a' = 3 m/s²
2nd law of motion : The rate of change of momentum is directly proportional to the force applied and it takes place in the direction of the force.
i.e. F ∝ m(v - u)/t
Answer:
2nd Option
Explanation:
Hope it help you
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Answer
The force would accelerate the 400kg mass by 3m/s² .
Explanation:-
Given that ,a force (F) accelerates a body of mass 600kg by 2m/s².
So, firstly let's calculate the force (F) by Newton's 2nd law of motion :-
F = ma
Where :-
• F is the force.
• m is mass of the body.
• a is the acceleration.
Substituting values, we get :-
⇒ F = 600(2)
⇒ F = 1200 N
________________________________
Now, in the 2nd case we have :-
• m' = 400 kg
• F = 1200 N
• a' = ?
Again substituting values in the 2nd equation of motion, we get :-
⇒ F = m'a'
⇒ a' = F/m'
⇒ a' = 1200/400
⇒ a' = 3 m/s²
Some Extra Information:-
2nd law of motion : The rate of change of momentum is directly proportional to the force applied and it takes place in the direction of the force.
i.e. F ∝ m(v - u)/t
Answer:
2nd Option
Explanation:
Hope it help you