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arunimakon
@arunimakon
July 2021
2
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answer it guys, two times I've skipped to upload the attachment ...
This time , plz do answer...☝☝☝
Answers & Comments
AneekBiswas1
Here is your answer......
In triangle ABP and triangle ACQ
i)Angle BOY = Angle COX (vertically opposite angles)
ii)XY = XY (common)
iii)Angle XAY = Angle XAY (common)
Therefore, triangle ABP congruent triangle ACQ(ASA)
Therefore, Area of triangle ABP = Area of triangle ACQ (Congruent triangles have equal area)Proved..
Hope you like it....
Mark as brainliest....
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Thanks 2
princetiwari6868
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Answers & Comments
In triangle ABP and triangle ACQ
i)Angle BOY = Angle COX (vertically opposite angles)
ii)XY = XY (common)
iii)Angle XAY = Angle XAY (common)
Therefore, triangle ABP congruent triangle ACQ(ASA)
Therefore, Area of triangle ABP = Area of triangle ACQ (Congruent triangles have equal area)Proved..
Hope you like it....
Mark as brainliest....
dbbdjsjdjjr my ehsbndnsnsmsmsmslskkdjtvb