Since nothing is mentioned in the question, you have to assume steady state condition. Hence in steady state condition the capacitor acts as an open circuit. (check the image)..
Hope it Helps You mate..
Good Luck ✌️✌️
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AleXXa
sry... it's nt asked in any competitive Xm... just test series
Answers & Comments
Since nothing is mentioned in the question, you have to assume steady state condition. Hence in steady state condition the capacitor acts as an open circuit. (check the image)..
Hope it Helps You mate..
Good Luck ✌️✌️