Answer:
Let x=4a-3b, y=b-3a, z=2b-a
On adding x+y+z=0
therefore, x³+y³+z³=3xyz
Substituting x,y,z values we get
(4a-3b)³+(b-3a)³+(2b-a)³=3(4a-3b)(b-3d)(2b-a)
Step-by-step explanation:
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Answer:
Let x=4a-3b, y=b-3a, z=2b-a
On adding x+y+z=0
therefore, x³+y³+z³=3xyz
Substituting x,y,z values we get
(4a-3b)³+(b-3a)³+(2b-a)³=3(4a-3b)(b-3d)(2b-a)
Step-by-step explanation:
..
it's a humble request
Step-by-step explanation:
HOPE THIS HELP YOU........