Michael finished colouring a picture in 7/12 hour. Vaibhav finished colouring the same picture in 3/4 hour. Who worked longer? By what fraction was it longer?
Solution:
Let's compare the fractions and decide which one is larger.
Time is taken by Michael = 7/12 hour
Time is taken by Vaibhav = 3/4 hour
= (3×3) / (4×3) (converting into like fractions)
= 9/12 hour
Since, 9/12 > 7/12
Therefore, Vaibhav worked for longer.
Difference = 9/12 − 7/12
= 2/12
= 1/6 hour
Thus, Vaibhav took 1/6 hour more than Michael
is these ans is correct
Answer:
Time Michael took = [tex]\frac{7}{12}[/tex]
Time Vaibhav took = [tex]\frac{3}{4}[/tex]
Step 1: Make them like fractions
[tex]\frac{7}{12}[/tex] and [tex]\frac{3}{4}[/tex]
=> [tex]\frac{7}{12}[/tex] and [tex]\frac{3X3}{4X3}[/tex]
=> [tex]\frac{7}{12}[/tex] and [tex]\frac{9}{12}[/tex]
Clearly, Vaibhav took the more time than Michael.
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Answers & Comments
Michael finished colouring a picture in 7/12 hour. Vaibhav finished colouring the same picture in 3/4 hour. Who worked longer? By what fraction was it longer?
Solution:
Let's compare the fractions and decide which one is larger.
Time is taken by Michael = 7/12 hour
Time is taken by Vaibhav = 3/4 hour
= (3×3) / (4×3) (converting into like fractions)
= 9/12 hour
Since, 9/12 > 7/12
Therefore, Vaibhav worked for longer.
Difference = 9/12 − 7/12
= 2/12
= 1/6 hour
Thus, Vaibhav took 1/6 hour more than Michael
is these ans is correct
Verified answer
Answer:
Time Michael took = [tex]\frac{7}{12}[/tex]
Time Vaibhav took = [tex]\frac{3}{4}[/tex]
Step 1: Make them like fractions
[tex]\frac{7}{12}[/tex] and [tex]\frac{3}{4}[/tex]
=> [tex]\frac{7}{12}[/tex] and [tex]\frac{3X3}{4X3}[/tex]
=> [tex]\frac{7}{12}[/tex] and [tex]\frac{9}{12}[/tex]
Clearly, Vaibhav took the more time than Michael.
If this answer was helpful to you in any way then please mark me THE BRAINLIEST (*^_^*)
↓ And please click this button!