Answer:
Using Newton's second law of motion F=ma:
⇒F=2000 kg×2.00 m s−2
⇒F=4000.00 kg m s−2
∴F=4000.00 N
The net force needed is 4000 N.
[tex]\mathsf {F\: =2000\: kg\times 2.00 \:m s^{−2}}[/tex]
[tex]\mathsf {F\: =4000.00\: kg\: m s^{−2}}[/tex]
[tex]\mathsf {F\: = 4000.00 \: N}[/tex]
The net force needed is [tex]\mathsf {4000\: N}[/tex].
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Answers & Comments
Answer:
Using Newton's second law of motion F=ma:
⇒F=2000 kg×2.00 m s−2
⇒F=4000.00 kg m s−2
∴F=4000.00 N
The net force needed is 4000 N.
Using Newton's second law of motion F=ma:
[tex]\mathsf {F\: =2000\: kg\times 2.00 \:m s^{−2}}[/tex]
[tex]\mathsf {F\: =4000.00\: kg\: m s^{−2}}[/tex]
[tex]\mathsf {F\: = 4000.00 \: N}[/tex]
The net force needed is [tex]\mathsf {4000\: N}[/tex].