(lmao this is legit way too much but anyway)
A. factoring quadratic polynomials
1. (x + 3)(x + 1)
2. (x - 2)(x - 1)
3. (a - 3)(a - 2)
4. (y - 4)(y + 3)
5. (b + 5)(b - 2)
6. (x + 6)(x - 2)
7. (c - 5)(c - 3)
8. (x + 7)(x - 5)
9. (x - 15)(x + 2)
10. (x + 16)(x - 3)
11. (x - 15)(x - 5)
12. (x - 20)(x + 3)
13. (a + 12)(a - 3)
14. (b - 22)(b - 2)
15. (m + 14)(m + 5)
16. (r - 9)(r + 8)
17. (p - 16)(p + 3)
18. (y + 13)(y + 3)
19. (n - 12)(n + 9)
20. (d - 24)(d - 5)
B. factoring trinomials
1. (2x + 1)(x + 1)
2. (2x - 1)(x - 2)
3. (3x + 2)(x - 3)
4. (2x - 5)(x - 1)
5. (3x + 4)(2x - 5)
6. (4x + 1)(x - 6)
7. (5a - 4)(2a - 3)
8. (6m - 1)(2m + 7)
9. 3(y - 5)(2y + 3)
10. (3x + 4)(x + 11)
11. (6x - 7)(x + 3)
12. (5x + 6)(5x - 3)
13. (4x + 3)(2x - 1)
14. (3y + 8)(3y - 5)
15. (7p + 4)(2p + 5)
16. (9r + 1)(r - 6)
17. (10c - 3)(2c + 3)
18. (4x² - 3)(x² + 2)
19. (12y² + 1)(x² - 1) or (12y² + 1)(x + 1)(x - 1)
20. (xⁿ - 5)(xⁿ - 3)
C. Solving
1. (5x - 1)
2. (3x + 7)cm
3. (14x + 6)m
4. -16 and 3
5. No, it cannot be. The trinomial x² + x + 1 has imaginary roots.
6. factors: (3x + 17)(x + 3)
3x + 17 = 317
x + 3 = 103
myg that was a lot i crei
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Answers & Comments
Verified answer
(lmao this is legit way too much but anyway)
A. factoring quadratic polynomials
1. (x + 3)(x + 1)
2. (x - 2)(x - 1)
3. (a - 3)(a - 2)
4. (y - 4)(y + 3)
5. (b + 5)(b - 2)
6. (x + 6)(x - 2)
7. (c - 5)(c - 3)
8. (x + 7)(x - 5)
9. (x - 15)(x + 2)
10. (x + 16)(x - 3)
11. (x - 15)(x - 5)
12. (x - 20)(x + 3)
13. (a + 12)(a - 3)
14. (b - 22)(b - 2)
15. (m + 14)(m + 5)
16. (r - 9)(r + 8)
17. (p - 16)(p + 3)
18. (y + 13)(y + 3)
19. (n - 12)(n + 9)
20. (d - 24)(d - 5)
B. factoring trinomials
1. (2x + 1)(x + 1)
2. (2x - 1)(x - 2)
3. (3x + 2)(x - 3)
4. (2x - 5)(x - 1)
5. (3x + 4)(2x - 5)
6. (4x + 1)(x - 6)
7. (5a - 4)(2a - 3)
8. (6m - 1)(2m + 7)
9. 3(y - 5)(2y + 3)
10. (3x + 4)(x + 11)
11. (6x - 7)(x + 3)
12. (5x + 6)(5x - 3)
13. (4x + 3)(2x - 1)
14. (3y + 8)(3y - 5)
15. (7p + 4)(2p + 5)
16. (9r + 1)(r - 6)
17. (10c - 3)(2c + 3)
18. (4x² - 3)(x² + 2)
19. (12y² + 1)(x² - 1) or (12y² + 1)(x + 1)(x - 1)
20. (xⁿ - 5)(xⁿ - 3)
C. Solving
1. (5x - 1)
2. (3x + 7)cm
3. (14x + 6)m
4. -16 and 3
5. No, it cannot be. The trinomial x² + x + 1 has imaginary roots.
6. factors: (3x + 17)(x + 3)
3x + 17 = 317
x + 3 = 103
myg that was a lot i crei