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Answer:

To determine the correct oxidation numbers, let's break down each compound:

1. Fe0:

Fe0 refers to elemental iron, where the oxidation number is always considered as 0.

2. KM04:

KM04 represents potassium manganate (VII), which consists of the potassium ion (K+) and the permanganate ion (MnO4-). The combined charge of the compound is zero, meaning the sum of the oxidation numbers must be zero. Since there is only one potassium ion, which has a fixed oxidation number of +1, we can determine the oxidation number of the permanganate ion (MnO4-).

Using the information we have:

(+1) + (x) + 4(-2) = 0, where x represents the oxidation number of Mn.

Simplifying the equation:

+1 + x - 8 = 0

x - 7 = 0

x = +7

Therefore, the oxidation number of the underlined ion (Mn) in KM04 is +7.

3. A1203:

A1203 refers to aluminum oxide, which consists of aluminum ions (Al3+) and oxide ions (O2-). Again, the combined charge of the compound is zero. Since there are two aluminum ions (Al3+) and three oxide ions (O2-), we can determine the oxidation number of aluminum.

Using the information we have:

2(x) + 3(-2) = 0, where x represents the oxidation number of Al.

Simplifying the equation:

2x - 6 = 0

2x = 6

x = +3

Therefore, the oxidation number of the underlined ion (Al) in A1203 is +3.

Correct answers:

1. Fe0 = 0

2. KM04 = +7

3. A1203 = +3

Explanation:

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Answer:

- The oxidation number of Fe⁰ is 0.

- The oxidation number of Mn in KMnO₄ is +7.

- The oxidation number of Al in Al₂O₃ is +3.