centre=(-1,-1) let the line perpendicular to x-y+8=0 be x-y+c=0 since (-1,-1) lies on it hence will satisfy
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saurabhsemalti
not parallel,, perpendicular... writing mistake
faiza10
Centre of circle eqn is given as centre=(-g,-f) for x^2 + y^2 +2gx+2fy+c=0 here centre is (-1,-1) then...for that line slope=-a/b = -1/-1 = 1 given ...line is perpendicular so slope becomes -1 eqn of straight line is y-y1 = slope ×(x-x1) y+1= -1 (x+1) y+1=-x-1 x+y+2=0 is final equation pls mark as as brainiest if it is correct
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centre=(-1,-1)
let the line perpendicular to x-y+8=0 be x-y+c=0
since (-1,-1) lies on it hence will satisfy
mark as brainliest if helped
centre=(-g,-f) for x^2 + y^2 +2gx+2fy+c=0
here centre is (-1,-1)
then...for that line
slope=-a/b = -1/-1 = 1
given ...line is perpendicular so slope becomes -1
eqn of straight line is
y-y1 = slope ×(x-x1)
y+1= -1 (x+1)
y+1=-x-1
x+y+2=0
is final equation
pls mark as as brainiest if it is correct