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July 2022 2 22 Report

HK281 Given.... sum f=N=120

summation X = 50. let A=50

class. f. Xi. di=Xi-A fidi
0-20. 17. 10. -40 -680
20-40. x. 30. -20. -20x
40-60. 32. 50. 00. 00
60-80. y. 70. 20. 20y
80-100. 19. 90. 40 760
sumf=N=68+x+y sumfidi=80-20x+20y

we have

N =120
68+x+y=120
x+y=120-68
x+y=52.... ...................i

we have

sum x(mean)=A+ sumfidi/sumfi

50=50+ 80-20x+20y/120

50-50=20(4-x+y)/120
0. =4-x+y/10

4-x+y=0x10
4-x+y=0
-x+y=-4
-(x-y) =-4
x-y=4
x=4+y. ..... ii

now from i and ii

4+y+y=52
4+2y=52
2y=52-4
2y=48
y=48/2
y=24... .iii

now from ii and iii

x=y+4
x=4+24
x=28

.. ..hope this helps you......

Mehak191 ty

HK281 if you get option then mark it as brainaliest OK plzz

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