Analie went to market and bought the ingredients for pancit bihon. She bought 3 kilograms of pancit bihon for ₱60.75 each kilogram and 2 liters of soy sauce for ₱44.50 each. How much did she need to pay?
Analie went to market and bought the ingredients for pancit bihon. She bought 3 kilograms of pancit bihon for ₱60.75 each kilogram and 2 liters of soy sauce for ₱44.50 each. How much did she need to pay?
Given:
Analie bought 3 kilograms of pancit bihon for ₱60.75 each kilogram and 2 liters of soy sauce for ₱44.50 each.
Asked:
How much did she need to pay?
Proccess:
Multiplication / Multiple / Times
Addition / Adding / Add
Solution:
60.75 × 3 = 182.25
44.50 × 2 = 89
182.25 + 89 = 271.25
Answer:
Analie need to pay ₱271.25 for 3 kilograms of pancit bihon and 2 liters of soh sauce.
Answers & Comments
Answer:
given: ₱60.75 and ₱44.50
asked: how much did she need to pay?
process: Addition
solution:
₱60.75
+₱44.50
_________
₱105.25
answer: ₱105.25
Answer:
Analie went to market and bought the ingredients for pancit bihon. She bought 3 kilograms of pancit bihon for ₱60.75 each kilogram and 2 liters of soy sauce for ₱44.50 each. How much did she need to pay?
Given:
Analie bought 3 kilograms of pancit bihon for ₱60.75 each kilogram and 2 liters of soy sauce for ₱44.50 each.
Asked:
How much did she need to pay?
Proccess:
Multiplication / Multiple / Times
Addition / Adding / Add
Solution:
60.75 × 3 = 182.25
44.50 × 2 = 89
182.25 + 89 = 271.25
Answer:
Analie need to pay ₱271.25 for 3 kilograms of pancit bihon and 2 liters of soh sauce.
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