Answer:
120 kg is the answer
100kg of an ore contains 15kg of iron. Let mass required to obtain 18kg of iron be 'x'. Then, 15/100 * x = 18kg ⇒ x = 1800kg/15 = 120kg. ∴ Mass required to obtain 18kg of iron is '120kg'.
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Answer:
120 kg is the answer
Answer:
100kg of an ore contains 15kg of iron. Let mass required to obtain 18kg of iron be 'x'. Then, 15/100 * x = 18kg ⇒ x = 1800kg/15 = 120kg. ∴ Mass required to obtain 18kg of iron is '120kg'.