An object weighs 10 N in air. When immersed fully in water, it weighs only 8 N ....

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May 2021 2 26 Report

An object weighs 10 N in air. When immersed fully in water, it weighs only 8 N . Find the weight of the liquid displaced with the object will be??

MasterYaduvanshi Hello here is your answer by Sujeet yaduvanshi ☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝

Solution:-

Object weight in air=10N
Object weight in immersed water=8N

then,

Liquid displaced with the object=10N-8N=2N

that's all

@Sujeet

rakeshmohata ♥️Hope u like my process♥️
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According to Archimedes principle,
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$\bf \: = > buoyancy \: \: force = weight \: \: of \: \: the \: liquid \: \: dispersed$

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So total weight of object in air = $\bf \: 10 \: \: N$

Total weight of object in water= $\bf \: 8 \: \: N$

So..
Total buoyancy force = 10 - 8 =2N

So..
Total liquid dispersed weighs = $\bf \: 2 \: \: N$

_____________________________
♥️Hope this is ur required answer♥️

❤️Proud to help you ❤️

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