Distance covered in first 10 seconds is 100 m

So,

S = ut + 0.5at²

100 m = 0 + (0.5a (10 s)²)

a = 2 m/s²

Distance covered in first 15 seconds

S = ut + 0.5at²

= 0 + (0.5 × 2 m/s² × (15 s)²)

= 225 m

Distance covered in next 5 seconds = Distance covered in first 15 seconds - Distance covered in first 10 seconds

= 225 m - 100 m

= 125 m

Distance covered in next 5 seconds is 125 m

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 ⟦H⟧⟦E⟧⟦L⟧⟦P⟧⟦S⟧

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