Answer:

Height of object h1=2 cm

Height of real image h2=−3 cm

Magnification m=h2h1=−32=−1.5

We know that, m=−vu

Here, object distance u=−16cm

Substituting the value, we get

−1.5=−v(16)⇒1.5=v16⇒=16×(−1.5)=−24c

The position of image is 24 cm in front of the mirror (negative sign indicates that the image is. on the left side of the mirror).

Answer:

Here h

1

= 2 cm, u = -16 cm, h

2

= -3 cm (Since image is real and inverted.)

∵m=

h

1

h

2

=−

u

v

∴v=

h

1

−h

2

u=

2

3

×(−16)=−24cm

f

1

=

v

1

+

u

1

=−

24

1

−

16

1

=

48

−2−3

=

48

−5

;f=

5

−48

=−9.6cm

Explanation:

Hi