Answer:
3 tables per row
Step-by-step explanation:
Let x be the number of rows
Let x-3 be the number of tables per row
(x)(x-3)=18
x² - 3x = 18
x² - 3x - 18 = 0
(x-6)(x+3) = 0
x= 6, -3
There is two possible number of rows, 6 and -3, but take into account that 6 is a positive number, therefore, it will be the possible number of rows.
Substitution:
(6)(6-3)=18
(6)(3)=18
18=18 TRUE
Therefore there are 6 rows with 3 tables each.
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Answers & Comments
Answer:
3 tables per row
Step-by-step explanation:
Let x be the number of rows
Let x-3 be the number of tables per row
(x)(x-3)=18
x² - 3x = 18
x² - 3x - 18 = 0
(x-6)(x+3) = 0
x= 6, -3
There is two possible number of rows, 6 and -3, but take into account that 6 is a positive number, therefore, it will be the possible number of rows.
Substitution:
(6)(6-3)=18
(6)(3)=18
18=18 TRUE
Therefore there are 6 rows with 3 tables each.