An engine works at 600 rpm and performs 1000J of work in one cycle. If the engine runs for 20 minutes, find

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October 2023 1 4 Report

An engine works at 600 rpm and performs 1000J of work in one cycle. If the engine runs for 20 minutes, find the total work done by the engine.

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nitirajsingh094

Explanation:

Given:

Given:Heat absorbed, Q

Given:Heat absorbed, Q 1

Given:Heat absorbed, Q 1 =1000J

Given:Heat absorbed, Q 1 =1000JHeat rejected, Q

Given:Heat absorbed, Q 1 =1000JHeat rejected, Q 2

Given:Heat absorbed, Q 1 =1000JHeat rejected, Q 2 =600J

Given:Heat absorbed, Q 1 =1000JHeat rejected, Q 2 =600JTemperature of reservoir, T

Given:Heat absorbed, Q 1 =1000JHeat rejected, Q 2 =600JTemperature of reservoir, T 1

Given:Heat absorbed, Q 1 =1000JHeat rejected, Q 2 =600JTemperature of reservoir, T 1 =127°C=127+273=400K

Given:Heat absorbed, Q 1 =1000JHeat rejected, Q 2 =600JTemperature of reservoir, T 1 =127°C=127+273=400KTo find:

Given:Heat absorbed, Q 1 =1000JHeat rejected, Q 2 =600JTemperature of reservoir, T 1 =127°C=127+273=400KTo find:Efficiency of the engine, η=?

Given:Heat absorbed, Q 1 =1000JHeat rejected, Q 2 =600JTemperature of reservoir, T 1 =127°C=127+273=400KTo find:Efficiency of the engine, η=?Te

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