an electric iron of 1100W is operated for 2 hrs daily. what will be the electrical consumption expenses for that in the month of April? (the electric company charges Rs 5 per unit of energy).with explanation please
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
______
your answer is "330"
Explainatioan
_______
Energy = 1100W = 1.1Kw
Energy=power*time=1.1(kw)*2(hr)=2.2kwh
Energy used in a day=2.2 unit
Energy used in 30 days= 2.2×30unit = 66unit
Total cost=66×5=330 rs
hope it will help you..
This is the easy way to understand this sum
Given.
P=1100w=1.1kwh (convert w into kwh)
Time=2hrs
To find
Cost to spend time for april=?
Solution
Work=p×t
=1.1×2
Work done to spend time for 1 day = 2.2kwh=2.2 units
Energy consumed in 1 day = work done in 1 day
Energy consumed in 1 day = 2.2units
Cost to operate for 1 day × rate of units consumed in 1 day
=2.2×5
=Rs 11
Cost to operate for April
=cost To operate for 1 day × 30
=11×30
=Rs 330