An assembly hall is 45 m long, 30 m broad and 16 m high. It has five doors, each measuring 4 m by 8.5 m and four windows 2.5 m by 1.6 m each. Find (i) the cost of papering its walls at the rate of 35 per m²; ii) the cost of carpeting its floor at the rate of 154 per m².
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Answers & Comments
Step-by-step explanation:
Area of 4 walls of the room = [2(1+b)*h]
So, Area of the 4 walls of the room which is to be papering is = [2(45+30)*16] m²
Now the area of the four walls is = 2400 m²
Now we have to find the area of both the five doors and four windows. So here we as follow,
Area of five doors = (4*3.5)m² = 14 m²
As there are five doors so we have to multiply 14 with 5, so = (14*5)m² = 70 m²
Now, Area of four windows =(2.5*1.6)m² = 4m² is the area of 1 window.
As we are having 4 windows we would multiply 4 with 4, so area of four windows is =(4*4)m² = 14m²
Now, area not to be papered = (Area of the doors)+(Area of the windows) = (14+70)m² = 86m² is the area of both the doors and windows and also the area which not to be papered.
Now area to be papered = ( Area of the 4 walls )-(Area of the doors and windows) = (2400-86)m² = 2314 m²
2314m² to be papered.
Now,
1 m² of wall would cost 35 to get papered;
2314 m² of wall would cost = (2314*35) to get papered. so the cost to paper the walls:
₹80990
Now, We know that to find the floor area, we just have to multiply the length and breadth of the walls of the assembly or =(l*b) cube.units.
So, the area is = (45x30) = 1350 m²
Now,
1m² of the floor will cost 154 to carpet it.
1350m² of the floor will cost (1350*154)
₹207900
So, here are the two answers finally,
the cost of papering the wall = ₹80990.
the cost of carpeting the floor = ₹207900.