An airplane flying at an altitude of 7.2 miles passes directly over an observer. Let theta be the angle of elevation from the standing point of the observer to the airplane. Find the distance d from the observer to the plane when: theta=58 degrees
An airplane, flying at an altitude of y = 4.7 miles, is on a flight path that passes directly over an observer (see figure). If θ is the angle of elevation from the observer to the plane, find the distance from the observer to the plane for each value of θ.
theta = 30 degrees
I just want to know if this is the right way to solve this problem:
sin(30 deg) = 4.7/x
x = 1/2
4.7/(1/2
pa brainlest po
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shunreialy
miss anlayo ng tanong ko sa sagot mo, wrong question yung nilagay mk eh^°^
Answers & Comments
An airplane, flying at an altitude of y = 4.7 miles, is on a flight path that passes directly over an observer (see figure). If θ is the angle of elevation from the observer to the plane, find the distance from the observer to the plane for each value of θ.
theta = 30 degrees
I just want to know if this is the right way to solve this problem:
sin(30 deg) = 4.7/x
x = 1/2
4.7/(1/2
pa brainlest po