An aircraft carrier is 3200 miles southwest of an enemy oil base. Its planes have a radius
of action of 1000 miles. If the carrier sails N 40 O E, how far at least will it travel so that
the oil base comes within the range of the radius of action of the planes?
of action of 1000 miles. If the carrier sails N 40 O E, how far at least will it travel so that
the oil base comes within the range of the radius of action of the planes?
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Answer:
let 'x' be the velocity of one plane
'y' be the velocity of the other
knowing that the formula for velocity is defined by the equation :
where v is the velocity
d is the distance traveled
t is the time
modifying the equation you'll have:
since you are given the distance as 1,140mi and the time traveled as 1.5hours
and that the other plane is traveling 10mph faster than the other then you'll have:
xt + yt = 1,140mi -----equation 1
x = y + 10mph -----equation 2
substituting equation 2 to 1 and having the time as 1.5hrs,
xt +yt = 1,140
(y+10)(1.5) + y(1.5) = 1,140
1.5y +15 + 1.5y = 1,140
3y = 1,140 - 15
3y = 1125
y = 375mph
substitute to equation 2
x = y + 10
x = 375 + 10
x = 385mph
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