[tex]\large{\red{\star} \: {\underline{\underline{\purple{\sf{Solution \: :-}}}}}}[/tex]
Given :- _yz _ zX _ xyx _ Z _ ZXzxy ? complete the series ?
[tex]\red{\underline{ \rule{190pt}{2pt}} }[/tex]
Breaking the series in three we get,
→ _yz | _ zX | _ xy | x _ Z | _ ZX | zxy
as we can see that, each part has three alphabets X , Y and Z and the alphabets are changing places in a cyclic manner .
then,
→ xyz | y zX | z xy | x y Z | y ZX | zxy
therefore, Compete series will be ,
→ xyzyzXzxyxyZyZXzxy .
Hence, we can conclude that, "xyzyy" will compete the pattern .
[tex]\small\pink{Hope \: it \: helps}[/tex]
Answer:
Hence, we can conclude that, "xyzyy" will compete the pattern
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Answers & Comments
[tex]\large{\red{\star} \: {\underline{\underline{\purple{\sf{Solution \: :-}}}}}}[/tex]
Given :- _yz _ zX _ xyx _ Z _ ZXzxy ? complete the series ?
[tex]\red{\underline{ \rule{190pt}{2pt}} }[/tex]
Answer :-
Breaking the series in three we get,
→ _yz | _ zX | _ xy | x _ Z | _ ZX | zxy
as we can see that, each part has three alphabets X , Y and Z and the alphabets are changing places in a cyclic manner .
then,
→ xyz | y zX | z xy | x y Z | y ZX | zxy
therefore, Compete series will be ,
→ xyzyzXzxyxyZyZXzxy .
Hence, we can conclude that, "xyzyy" will compete the pattern .
[tex]\red{\underline{ \rule{190pt}{2pt}} }[/tex]
[tex]\small\pink{Hope \: it \: helps}[/tex]
|| Thank You ||
Answer:
Breaking the series in three we get,
→ _yz | _ zX | _ xy | x _ Z | _ ZX | zxy
as we can see that, each part has three alphabets X , Y and Z and the alphabets are changing places in a cyclic manner .
then,
→ xyz | y zX | z xy | x y Z | y ZX | zxy
therefore, Compete series will be ,
→ xyzyzXzxyxyZyZXzxy .
Hence, we can conclude that, "xyzyy" will compete the pattern