Algebraic expression of an arithmetic sequence is 6n - 2
1) write the 1st term and the 10th term ?
2) what is the sum of 5th and 6th form ?
3) find the sum of the first 10 terms of this sequence?
1) write the 1st term and the 10th term ?
2) what is the sum of 5th and 6th form ?
3) find the sum of the first 10 terms of this sequence?
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Answer:
a1=6×1-2
=6-2
=4
a2=6×2-2
=12-2
=10
d=a2-a1
=10-4
=6
therefore,
1st term=4
10th term a10=a+(n-1)d
=4+(10-1)6
=4+9×6
=4+54
=58
sum of 5th and 6th term=a5+a6
=[4+(5-1)6]+[4+(6-1)6]
=(4+4×6)+(4+5×6)
=(4+10)+(4+30)
=14+34
=48
sum of 10th term[S10]=10/2[2×4+(10-1)6]
=5[8+9×6]
=5(8+15)
=5×23
=115
Answer:
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