To calculate the amount in Aditya's account at the end of each year, we can use the formula for compound interest:
{tex} \[ A = P \times \left(1 + \frac{r}{100}\right)^n \] {/tex}
Where:
- (A) is the amount at the end of the investment period.
- (P) is the principal amount (initial investment), which is $30,000 in this case.
- (r) is the annual interest rate, which is 10%.
- (n) is the number of years.
Let's calculate the amounts for each year:
(a) After one year:
[tex] \[ A = 30000 \times \left(1 + \frac{10}{100}\right)^1 = 30000 \times 1.1 = 33000 \] [/tex]
So, the amount in Aditya's account after one year will be 33,000.
(b) After two years:
[tex] [ A = 30000 \times \left(1 + \frac{10}{100}\right)^2 = 30000 \times 1.21 = 36300 \] [/tex]
The amount in his account after two years will be 36,300.
(c) After three years:
[tex] \[ A = 30000 \times \left(1 + \frac{10}{100}\right)^3 = 30000 \times 1.331 = 39930 \] [/tex]
The amount in his account after three years will be 39,930.
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Verified answer
To calculate the amount in Aditya's account at the end of each year, we can use the formula for compound interest:
{tex} \[ A = P \times \left(1 + \frac{r}{100}\right)^n \] {/tex}
Where:
- (A) is the amount at the end of the investment period.
- (P) is the principal amount (initial investment), which is $30,000 in this case.
- (r) is the annual interest rate, which is 10%.
- (n) is the number of years.
Let's calculate the amounts for each year:
(a) After one year:
[tex] \[ A = 30000 \times \left(1 + \frac{10}{100}\right)^1 = 30000 \times 1.1 = 33000 \] [/tex]
So, the amount in Aditya's account after one year will be 33,000.
(b) After two years:
[tex] [ A = 30000 \times \left(1 + \frac{10}{100}\right)^2 = 30000 \times 1.21 = 36300 \] [/tex]
The amount in his account after two years will be 36,300.
(c) After three years:
[tex] \[ A = 30000 \times \left(1 + \frac{10}{100}\right)^3 = 30000 \times 1.331 = 39930 \] [/tex]
The amount in his account after three years will be 39,930.