ACTIVITY: COMPUTE ME! Directions: Given the problem below, answer the following questions. Show your solutions to each question. The following data show the probabilities for the number of empanadas sold in Marcial O. Rañola Memorial School Canteen: Let E be the no. of empanadas sold E 0 1 2 3 4 5 6 7 8 9 10 P(E) 0.1 0.15 0.25 0.14 0.09 0.08 0.06 0.05 0.04 0.025 0.015 1. What is the probability that the number of empanadas sold is more than 5? 2. What is the probability that the number of empanadas sold is at most 8? 3. What is the probability that the number of empanadas sold was greater than 2 but less than 5?
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1. To find the probability that the number of empanadas sold is more than 5, we need to add up the probabilities of all the outcomes where E is greater than 5:P(E > 5) = P(E = 6) + P(E = 7) + P(E = 8) + P(E = 9) + P(E = 10)= 0.06 + 0.05 + 0.04 + 0.025 + 0.015= 0.195Therefore, the probability that the number of empanadas sold is more than 5 is 0.195.
2.To find the probability that the number of empanadas sold is at most 8, we need to add up the probabilities of all the outcomes where E is less than or equal to 8:P(E ≤ 8) = P(E = 0) + P(E = 1) + P(E = 2) + P(E = 3) + P(E = 4) + P(E = 5) + P(E = 6) + P(E = 7) + P(E = 8)= 0.1 + 0.15 + 0.25 + 0.14 + 0.09 + 0.08 + 0.06 + 0.05 + 0.04= 0.86Therefore, the probability that the number of empanadas sold is at most 8 is 0.86.
3.To find the probability that the number of empanadas sold was greater than 2 but less than 5, we need to add up the probabilities of all the outcomes where E is greater than 2 and less than 5:P(2 < E < 5) = P(E = 3) + P(E = 4)= 0.14 + 0.09= 0.23Therefore, the probability that the number of empanadas sold was greater than 2 but less than 5 is 0.23.
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