Answer:

First, you need the electron configurations of the elements of ammonia

, which are N and H

N = , meaning N has 3 valence electrons, since the last orbital, 2p, is incomplete with only 3 (remember that this must be p6)

H = , meaning H has 1 valence electron, since 1s should have 2 to be complete

Draw the individual atoms first. 3 Hydrogen atoms, 1 Nitrogen:

*

*N* , *H *H *H

**

Pair the sides with only one atoms:

**

H--N--H

|

H

Since all the valence electrons in the octet of electrons in Nitrogen is paired, we have hence shown how covalence bond formed from the combination of its atoms.