Activity 3: SOLVE ME
To solve the application problems in this section, transform the values of the variable to z
values.
1.
-
Alex scored 90 during the first periodic exam in Mathematics and 88 during the second periodic
exam. The scores in first periodic exam have a meanu = 83 and a standard deviation o = 9. Scores
in the second periodic exam have a mean u = 80 and a standard deviation o = 8. in which
periodic exam was his standing better, assuming that the scores in his periodicexams are normally
distributed?
On a final examination in Biology, the mean was 75 and the standard deviation was 12. Determine
the standard score of a student who received a score of 60 assuming that the scores are normally
distributed
2.
a
To solve the application problems in this section, transform the values of the variable to z
values.
1.
-
Alex scored 90 during the first periodic exam in Mathematics and 88 during the second periodic
exam. The scores in first periodic exam have a meanu = 83 and a standard deviation o = 9. Scores
in the second periodic exam have a mean u = 80 and a standard deviation o = 8. in which
periodic exam was his standing better, assuming that the scores in his periodicexams are normally
distributed?
On a final examination in Biology, the mean was 75 and the standard deviation was 12. Determine
the standard score of a student who received a score of 60 assuming that the scores are normally
distributed
2.
a
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Answers & Comments
Answer:
1. The second exam he standing better
Solution:
83 + 9 = 92 83 - 9 = 74
90 E ( 74, 92 )
80 + 8 = 88 80 - 8 = 72
88 E ( 72, 88 )
88 is closed to 88 then 90 close to 92
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