Answer:
7m and 12m
Explanation:
Take the length as x and width as y.
xy = 84 (1)
2x + 2y = 38
x = 19 - y (2)
Substitute (2) into (1)
19y - y^2 = 84
y^2 - 19y + 84 = 0
(y-12)(y-7) =0
or
Rectangular garden of length l and width w.
Area : lw = 84 sq m …..(1)
Perimeter : 2(l+w) = 38 m …..(2)
2(l + w) = 38
l + w = 19
l = (19 - w) …..(3)
Substitute: (3) in (1) : (19 - w)w = 84
19w - w^2 = 84
w^2 - 19w + 84 = 0
(w - 12)(w - 7) = 0
w = 7 or 12.
l = 19 - w
l = 12 or 7.
So, l = 12 m, and w = 7 m.
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Answers & Comments
Answer:
7m and 12m
Explanation:
Take the length as x and width as y.
xy = 84 (1)
2x + 2y = 38
x = 19 - y (2)
Substitute (2) into (1)
19y - y^2 = 84
y^2 - 19y + 84 = 0
(y-12)(y-7) =0
or
Rectangular garden of length l and width w.
Area : lw = 84 sq m …..(1)
Perimeter : 2(l+w) = 38 m …..(2)
2(l + w) = 38
l + w = 19
l = (19 - w) …..(3)
Substitute: (3) in (1) : (19 - w)w = 84
19w - w^2 = 84
w^2 - 19w + 84 = 0
(w - 12)(w - 7) = 0
w = 7 or 12.
l = 19 - w
l = 12 or 7.
So, l = 12 m, and w = 7 m.