ACTIVITY 1:
Transform each equation into standard form. Then, identify the values of a, b, and c. SHOW YOUR SOLUTIONS.
1. x2 – 6x = - 5
2. (2x + 1)(x – 3) = 0
3. 4x2 = x + 5
4. (x + 4)(x – 9) = 0
5. x2 – 25 = 0
6. (x + 4)(x – 2) = 4x
7. 13x – 36 = x2
8. (x – 3)2 = 12
9. 6x2 = - x + 1
10.2x(x + 5) = -3
Activity 2:
A. How did you find the activities?
B. How would you identify a quadratic equation
please help me to answer this.
Answers & Comments
1. x2 – 6x = - 5
x² - 6x + 5 = 0
where a = 1, b = -6, and c = 5
2. (2x + 1)(x – 3) = 0
2x² - 6x + x - 3 = 0
2x² - 5x - 3 = 0
where a = 2, b = -5, and c = -3
3. 4x2 = x + 5
4x² - x - 5 = 0
where a = 4, b = -1, and c = -5
4. (x + 4)(x – 9) = 0
x² - 9x + 4x - 36 = 0
x² - 5x - 36 = 0
where a = 1, b = -5, and c = -36
5. x2 – 25 = 0
where a = 1, b = 0, and c = -25
6. (x + 4)(x – 2) = 4x
x² - 2x + 4x - 8 = 4x
x² - 2x + 4x - 4x - 8 = 0
x² - 2x - 8 = 0
where a = 1, b = -2, and c = -8
7. 13x – 36 = x2
-x² + 13x - 36 = 0 (divided by -1)
x² - 13x + 36 = 0
where a = 1, b = -13, and c = 36
8. (x – 3)2 = 12
(x - 3) (x - 3) = 12
x² - 3x - 3x + 9 = 12
x² - 6x + 9 - 12 = 0
x² - 6x - 3 = 0
where a = 1, b = -6, and c = -3
9. 6x2 = - x + 1
6x² + x - 1 = 0
where a = 6, b = 1, and c = -1
10.2x(x + 5) = -3
2x² + 10x = -3
2x² + 10x + 3 = 0
where a = 2, b = 10, and c = 3
Activity 2:
A. How did you find the activities?
By following this standard form format ax²+bx+c=0
B. How would you identify a quadratic equation
Has a variable that’s squared and no variables with powers higher than 2 in any of the terms