According to the following reaction: 2Cu(s) + O_2(g) -> +2CuO(s)
a. If the percentage yield is 96.7% how many grams of CuO will be produced from 13.4g of Cu?
b. How many grams of Cu must you use to produce 5.00 x 10¹³mg CuO?
Please show me how to solve this problem. Thank you! <3
Answers & Comments
Answer:
Ammm aalamin nyo po yung tanong kasi wala po dyan yung tanong
Answer:
A. 16.22g CuO
B. 4.13 x 10¹³mg CuO
Explanation:
A.
yield= Practical value/ theory value*100
mol Cu~molCuO
1mol Cu~63.5gCu
13.4gCu = 0.211molCU
= 0.211 × (63.5 + 16)
=16.77g CuO= theory value
Practical value = 16.77 × 96.7/100
= 16.22g CuO
B:
theory value of CuO
= 5 x 10¹⁰gCuO/96.7 × 100
= 5.17 x 10¹⁰ gCuO
= 6.5 x 10⁸molCuO
= 6.5 x 10⁸molCuO
= 4.13 x 10¹⁰g CuO
= 4.13 x 10¹³mg CuO