ABCD is a rectangle and P is the midpoint of AB. DP is produced to meet CB at Q prove that area of rectangle ABCD equal to area of triangle DQC.
from chapter theorems on area
Pls answer fast today is my exam
from chapter theorems on area
Pls answer fast today is my exam
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ang pbq =ang dcq =90 ( given )
ang q =commen
therefor the tri are similar by aa
qb =bc
qb=1/2qc
dc=cb=1/2 qc ×dc
dc×cb=qb×dc