Let ABCD be a parallelogram. To show that ABCD is a rectangle, we have to prove that one of its interior angles is 90°. Hence, ∠B = ∠D = ∠C = ∠A = 90° [Since opposite angles of a parallelogram are equal]. Since ABCD is a parallelogram and one of its interior angles is 90°, ABCD is a rectangle.
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Answer:
Let ABCD be a parallelogram. To show that ABCD is a rectangle, we have to prove that one of its interior angles is 90°. Hence, ∠B = ∠D = ∠C = ∠A = 90° [Since opposite angles of a parallelogram are equal]. Since ABCD is a parallelogram and one of its interior angles is 90°, ABCD is a rectangle.
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