Answer:
Area of the triangle ABC
=s(s−a)(s−b)(s−c),
where s=21(a+b+c) and AB=35,BC=75,CA=44
Therefore, △ABC=77×(77−75)(77−44)(77−35)cm2
=77×2×33×42cm2
=7×11×2×3×11×2×3×7
=(7×11×2×3)=462
We have △ABC=△BOP+△COA+△AOB
Thus 463=21r(75+44+35)⇒r=6 cm
Therefore, radius of the circle is 6 cm.
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Answer:
Area of the triangle ABC
=s(s−a)(s−b)(s−c),
where s=21(a+b+c) and AB=35,BC=75,CA=44
Therefore, △ABC=77×(77−75)(77−44)(77−35)cm2
=77×2×33×42cm2
=7×11×2×3×11×2×3×7
=(7×11×2×3)=462
We have △ABC=△BOP+△COA+△AOB
Thus 463=21r(75+44+35)⇒r=6 cm
Therefore, radius of the circle is 6 cm.