AB is a chord of the circle and AOC is its diameter such that angle ACB = 50°. If AT is the tangent to the circle at the point A, then BAT is equal to ;)
9.4, AB is a chord of the circle and AOC is its diameter such that ∠ACB = 50°. If AT is the tangent to the circle at the point A, then ∠BAT is equal to. a. 65°
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Answer:
9.4, AB is a chord of the circle and AOC is its diameter such that ∠ACB = 50°. If AT is the tangent to the circle at the point A, then ∠BAT is equal to. a. 65°
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Answer:
From the given figure we know a tangent is perpendicular to the circle.
So, ∠TAC=∠TAB+∠BAC=90° [equation 1]
now in triangle ABC ∠ABC=90° [since the triangle is in a semi circle]
∠ABC+∠BCA+∠CAB=180°
therefore ∠CAB=180°−90°−50°=40°
so from equation 1 we get
∠TAB = 90° − ∠BAC = 90° − 40° = 50°.
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