AB is a chord of the circle and AOC is its diameter such that angle ACB = 50°. If AT is the tangent to the circle at the point A, then BAT is equal to ;)
Ohm's law states that the voltage or potential difference between two points is directly proportional to the current or electricity passing through the resistance, and directly proportional to the resistance of the circuit. The formula for Ohm's law is V=IR.
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Ohm's law states that the voltage or potential difference between two points is directly proportional to the current or electricity passing through the resistance, and directly proportional to the resistance of the circuit. The formula for Ohm's law is V=IR.
Answer:
Given, AB is a chord of the circle.
AOC is the diameter of the circle.
Also, ∠ACB = 50°
AT is the tangent of the circle.
We have to find the measure of the angle BAT.
We know that the angle in a semicircle is a right angle.
So, ∠CBA = 90°
We know that the sum of all three interior angles of a triangle is always equal to 180°
In triangle AOB,
∠CAB + ∠CBA + ∠ACB = 180°
∠CAB + 90° + 50° = 180°
∠CAB + 140° = 180°
∠CAB = 180° - 140°
∠CAB = 40° ------------------- (1)
We know that radius of a circle is perpendicular to the tangent at the point of contact.
From the figure,
OA ⟂ OT
So, ∠CAB + ∠BAT = 90°
Substitute (1) in the above expression,
40° + ∠BAT = 90°
∠BAT = 90° - 40°
∠BAT = 50°
Therefore, the measure of the angle BAT is 50°