Answer:
a⁴-a²b²+b⁴
Step-by-step explanation:
We know that a⁶+b⁶= (a²)³+(b²)³
let a²=x, b²=y
We also know that
x³+y³=(x+y)(x²-xy+y²)
substituting a²=x, b²=y
a⁶+b⁶=(a²+b²)(a⁴-a²b²+b⁴)
(a²+b²)(a⁴-a²b²+b⁴)÷(a²+b²)
=a⁴-a²b²+b⁴
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
Answer:
a⁴-a²b²+b⁴
Step-by-step explanation:
We know that a⁶+b⁶= (a²)³+(b²)³
let a²=x, b²=y
We also know that
x³+y³=(x+y)(x²-xy+y²)
substituting a²=x, b²=y
a⁶+b⁶=(a²+b²)(a⁴-a²b²+b⁴)
(a²+b²)(a⁴-a²b²+b⁴)÷(a²+b²)
=a⁴-a²b²+b⁴
Step-by-step explanation: