if α and β are the roots of the quadratic equation x^2 -6x -2 and if an=α n–βn then the value of a10-2a8/a9
Answers & Comments
shyamdeo141
Since alpha and beta are the roots of the eqn. x^2-6x-2=0 so, alpha + beta = - b/a =6 and, alpha * beta = c/a = -2 now a*n=alpha* n - beta* n a*n = n*(alpha - beta ) a = alpha - beta = sq.root of (alpha + beta)^2 - 4*alpha* beta i.e. a = sq.root of 6^2 - 4*(-2) a = root 44 so, (10*a -2*8a)/9a put the value of a we get ; req.ans = (10 -16 root 44) /9root 44.
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Prajal1
bro your answer is not matching with the options
shyamdeo141
ha bro maine galat qiustion lekar bana diya hai
Answers & Comments
x^2-6x-2=0
so, alpha + beta = - b/a
=6
and, alpha * beta = c/a = -2
now a*n=alpha* n - beta* n
a*n = n*(alpha - beta )
a = alpha - beta
= sq.root of (alpha + beta)^2 - 4*alpha* beta
i.e. a = sq.root of 6^2 - 4*(-2)
a = root 44
so, (10*a -2*8a)/9a
put the value of a
we get ; req.ans = (10 -16 root 44) /9root 44.