Step-by-step explanation:
Let a be the side of a square, l be the length and b be the breadth of rectangle.
As length of wire is constant, perimeter of both shapes would be same,
4a = 2(1+b )
40=2(12+b)
b=18 cm
Area of square=a2 = 102 = 100 cm2
Area of triangle= 1b = 12×8 = 216 cm2
⇒ Area of rectangle is greater by 116cm2
Answer:
I can't understand it sorry for this
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Verified answer
Step-by-step explanation:
Let a be the side of a square, l be the length and b be the breadth of rectangle.
As length of wire is constant, perimeter of both shapes would be same,
4a = 2(1+b )
40=2(12+b)
b=18 cm
Area of square=a2 = 102 = 100 cm2
Area of triangle= 1b = 12×8 = 216 cm2
⇒ Area of rectangle is greater by 116cm2
Answer:
I can't understand it sorry for this