A vessel having a volume of 0.6 m3 contains 3.0 kg of liquid water and water vapour mixture in equilibrium at a pressure of 0.65 MPa. (Refer saturated water pressure table A-5 from online) Calculate (9.1.) Find quality or X (9.2.) Mass and volume of liquid (9.3) Mass and volume of vapour
Answers & Comments
Explanation:
Given V = 0.6 m^3 Mass of water + Mass of Vapour = Mw + Mv = M = 3 kg Pressure of this mixture = P = 0.5 MPa…
Answer:
MARK ME AS THE BRAINIEST ANSWER ❤️❤️
Explanation:
A vessel having a volume of 0.6 m
A vessel having a volume of 0.6 m3
A vessel having a volume of 0.6 m3 contains 3.0 kg of a mixture of liquid water and water vapor in equilibrium at a pressure of 0.5 MPa. Calculate:
A vessel having a volume of 0.6 m3 contains 3.0 kg of a mixture of liquid water and water vapor in equilibrium at a pressure of 0.5 MPa. Calculate:(a) Mass and volume of liquid
A vessel having a volume of 0.6 m3 contains 3.0 kg of a mixture of liquid water and water vapor in equilibrium at a pressure of 0.5 MPa. Calculate:(a) Mass and volume of liquid(b) Mass and volume of vapor.
A vessel having a volume of 0.6 m3 contains 3.0 kg of a mixture of liquid water and water vapor in equilibrium at a pressure of 0.5 MPa. Calculate:(a) Mass and volume of liquid(b) Mass and volume of vapor.Quality of a Mixture:
A vessel having a volume of 0.6 m3 contains 3.0 kg of a mixture of liquid water and water vapor in equilibrium at a pressure of 0.5 MPa. Calculate:(a) Mass and volume of liquid(b) Mass and volume of vapor.Quality of a Mixture:In a mixture of saturated liquid water and saturated water vapor, the mass fraction of the vapor phase is known as the quality of the mixture. If the quality is equal to zero, instead of a mixture we have saturated liquid. Likewise, if the quality is one, we have saturated vapor.