A two digit number is 3 more than 4 times the sum of its digits.if 18 is added to the number,its digit are reversed. find the number
Answers & Comments
AshmitJain3107
Let the first digit be x and the second digit be y. Then, the number will be 10x+y. Acc. to the question, 10x+y = 4*(x+y)+3 10x-4x + y-4y = 3 6x - 3y = 3 Divide this by 3 we get, 2x-y=1. (1) Also, 10x+y+18 = 10y+x 10x-x+y-10 = -18 9x-9y = -18 Divide this by 9 we get, x-y=-2. (2) On doing (1) - (2) We get, x = 3. Then, y = x +2 y=3+2 y = 5. Therefore, the number is 35. Please mark as brainliest if it helps you....
Octane
Let the tens digit be x and ones digit be y original number =10x+y so equation 1 is 6x-3y=-3 reverse number =10y+x equation 2 is 9x-9y=-18 on adding equation 1 &2 we get x=7 putting the value of x in equation 1 we get 6x-3y=-3 6*7-3y=-3 42-3y=-3 42+3=3y 3y=45 y=45/3 y=15
Answers & Comments
Then, the number will be 10x+y.
Acc. to the question, 10x+y = 4*(x+y)+3
10x-4x + y-4y = 3
6x - 3y = 3 Divide this by 3 we get,
2x-y=1. (1)
Also, 10x+y+18 = 10y+x
10x-x+y-10 = -18
9x-9y = -18
Divide this by 9 we get,
x-y=-2. (2)
On doing (1) - (2) We get,
x = 3.
Then, y = x +2
y=3+2
y = 5.
Therefore, the number is 35.
Please mark as brainliest if it helps you....
original number =10x+y
so equation 1 is
6x-3y=-3
reverse number =10y+x
equation 2 is
9x-9y=-18
on adding equation 1 &2 we get
x=7
putting the value of x in equation 1 we get
6x-3y=-3
6*7-3y=-3
42-3y=-3
42+3=3y
3y=45
y=45/3
y=15