If we let "h" be the height of the trapezoid, the area of the trapezoid can be found by the formula:
Area = (base1 + base2)/2 * h
Since the trapezoid was broken into a rectangle and two equal triangles, the base of the rectangle is equal to the sum of the two triangle bases (2b), and the area of the rectangle can be found using the formula:
Area of rectangle = base * height
Since the height of the trapezoid and the rectangle are the same, we can equate the two formulas to find the height:
(b + 2b)/2 * h = b * h
Solving for h:
h = m2 / (b + b) = m2 / (2b)
So the height of the trapezoid is m2 / (2b), and the area of each triangle is:
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Answer:
If we let "h" be the height of the trapezoid, the area of the trapezoid can be found by the formula:
Area = (base1 + base2)/2 * h
Since the trapezoid was broken into a rectangle and two equal triangles, the base of the rectangle is equal to the sum of the two triangle bases (2b), and the area of the rectangle can be found using the formula:
Area of rectangle = base * height
Since the height of the trapezoid and the rectangle are the same, we can equate the two formulas to find the height:
(b + 2b)/2 * h = b * h
Solving for h:
h = m2 / (b + b) = m2 / (2b)
So the height of the trapezoid is m2 / (2b), and the area of each triangle is:
Area of triangle = (b * h) / 2 = (b * m2 / (2b)) / 2 = m2 / (2 * 2b) = m2 / 4b
So the area of each triangle is m2 / 4b.
Step-by-step explanation: